Dental Hygienist

Seymour, 1016 E Tipton St, Seymour, Indiana, United States of America Job Description Posted Thursday, August 27, 2026 at 4:00 AM Sign On Bonus: $10,000 Job ID: 833 Average Salary: $48/hour including additional earning opportunities Location: 1016 E Tipton St. Seymour, IN 47274 Job Type: Full Time Advance Your Career While Making a Difference in Patient Care Are you a skilled and dedicated Dental Hygienist seeking a meaningful opportunity in a patient-centered environment? Do you take pride in delivering high-quality care while collaborating with a team that values excellence and innovation? If so, we invite you to join our dental practice that invests in you as a dental provider. Why Join Us? Competitive Benefits Package: We provide a comprehensive compensation plan, including health insurance, retirement options, paid time off, and more. Continuous Professional Growth: Access continuing education opportunities and pathways for career advancement. Supportive Practice Culture: Collaborate with a close-knit team dedicated to mutual respect, innovation, and patient well-being. Advanced Technology: Practice with state-of-the-art equipment designed to elevate patient care and streamline your workflow. Requirements Hold an active Dental Hygiene License in the state that you're applying to OR be a Dental Hygiene student in an accredited Dental Hygiene program. Together, we’ll help our patients achieve brighter smiles and healthier lives. Any offer of employment is contingent upon the Company’s determination that the candidate has successfully passed a background check, including a drug screen. We are an equal-opportunity employer and consider all qualified candidates equally. #J-18808-Ljbffr